Talk:Richardson's theorem

This article is rated Start-class on Wikipedia's content assessment scale. It is of interest to the following WikiProjects:

Mathematics Low‑priority This article is within the scope of WikiProject Mathematics, a collaborative effort to improve the coverage of mathematics on Wikipedia. If you would like to participate, please visit the project page, where you can join the discussion and see a list of open tasks.MathematicsWikipedia:WikiProject MathematicsTemplate:WikiProject Mathematicsmathematics articles Low This article has been rated as Low-priority on the project's priority scale.

The article states at the present moment that if sqrt(x^2) is in E, then the A(x) = 0 is unsolveable. But sqrt(x^2) = x. This seems to be a weird formulation. — Preceding unsigned comment added by 217.227.80.156 (talk) 16:43, 29 June 2011 (UTC)[reply]

sqrt(x^2) is unequal to x for x < 0. —Mark Dominus (talk) 19:56, 29 June 2011 (UTC)[reply]