Bauer–Fike theorem

In what follows we assume that:

• A ∈ C^n,n is a diagonalizable matrix;
• V ∈ C^n,n is the non-singular eigenvector matrix such that A = VΛV ⁻¹, where Λ is a diagonal matrix.
• If X ∈ C^n,n is invertible, its condition number in p-norm is denoted by κ_p(X) and defined by:

${\displaystyle \kappa _{p}(X)=\|X\|_{p}\left\|X^{-1}\right\|_{p}.}$ 

Bauer–Fike Theorem. Let μ be an eigenvalue of A + δA. Then there exists λ ∈ Λ(A) such that:

${\displaystyle |\lambda -\mu |\leq \kappa _{p}(V)\|\delta A\|_{p}}$ 

Proof. We can suppose μ ∉ Λ(A), otherwise take λ = μ and the result is trivially true since κ_p(V) ≥ 1. Since μ is an eigenvalue of A + δA, we have det(A + δA − μI) = 0 and so

${\displaystyle {\begin{aligned}0&=\det(A+\delta A-\mu I)\\&=\det(V^{-1})\det(A+\delta A-\mu I)\det(V)\\&=\det \left(V^{-1}(A+\delta A-\mu I)V\right)\\&=\det \left(V^{-1}AV+V^{-1}\delta AV-V^{-1}\mu IV\right)\\&=\det \left(\Lambda +V^{-1}\delta AV-\mu I\right)\\&=\det(\Lambda -\mu I)\det \left((\Lambda -\mu I)^{-1}V^{-1}\delta AV+I\right)\\\end{aligned}}}$ 

However our assumption, μ ∉ Λ(A), implies that: det(Λ − μI) ≠ 0 and therefore we can write:

${\displaystyle \det \left((\Lambda -\mu I)^{-1}V^{-1}\delta AV+I\right)=0.}$ 

This reveals −1 to be an eigenvalue of

${\displaystyle (\Lambda -\mu I)^{-1}V^{-1}\delta AV.}$ 

Since all p-norms are consistent matrix norms we have |λ| ≤ ||A||_p where λ is an eigenvalue of A. In this instance this gives us:

${\displaystyle 1=|-1|\leq \left\|(\Lambda -\mu I)^{-1}V^{-1}\delta AV\right\|_{p}\leq \left\|(\Lambda -\mu I)^{-1}\right\|_{p}\left\|V^{-1}\right\|_{p}\|V\|_{p}\|\delta A\|_{p}=\left\|(\Lambda -\mu I)^{-1}\right\|_{p}\ \kappa _{p}(V)\|\delta A\|_{p}}$ 

But (Λ − μI)⁻¹ is a diagonal matrix, the p-norm of which is easily computed:

${\displaystyle \left\|\left(\Lambda -\mu I\right)^{-1}\right\|_{p}\ =\max _{\|{\boldsymbol {x}}\|_{p}\neq 0}{\frac {\left\|\left(\Lambda -\mu I\right)^{-1}{\boldsymbol {x}}\right\|_{p}}{\|{\boldsymbol {x}}\|_{p}}}=\max _{\lambda \in \Lambda (A)}{\frac {1}{|\lambda -\mu |}}\ ={\frac {1}{\min _{\lambda \in \Lambda (A)}|\lambda -\mu |}}}$ 

whence:

${\displaystyle \min _{\lambda \in \Lambda (A)}|\lambda -\mu |\leq \ \kappa _{p}(V)\|\delta A\|_{p}.}$ 

The theorem can also be reformulated to better suit numerical methods. In fact, dealing with real eigensystem problems, one often has an exact matrix A, but knows only an approximate eigenvalue-eigenvector couple, (λ^a, v^a ) and needs to bound the error. The following version comes in help.

Bauer–Fike Theorem (Alternate Formulation). Let (λ^a, v^a ) be an approximate eigenvalue-eigenvector couple, and r = Av^a − λ^av^a. Then there exists λ ∈ Λ(A) such that:

${\displaystyle \left|\lambda -\lambda ^{a}\right|\leq \kappa _{p}(V){\frac {\|{\boldsymbol {r}}\|_{p}}{\left\|{\boldsymbol {v}}^{a}\right\|_{p}}}}$ 

Proof. We can suppose λ^a ∉ Λ(A), otherwise take λ = λ^a and the result is trivially true since κ_p(V) ≥ 1. So (A − λ^aI)⁻¹ exists, so we can write:

${\displaystyle {\boldsymbol {v}}^{a}=\left(A-\lambda ^{a}I\right)^{-1}{\boldsymbol {r}}=V\left(D-\lambda ^{a}I\right)^{-1}V^{-1}{\boldsymbol {r}}}$ 

since A is diagonalizable; taking the p-norm of both sides, we obtain:

${\displaystyle \left\|{\boldsymbol {v}}^{a}\right\|_{p}=\left\|V\left(D-\lambda ^{a}I\right)^{-1}V^{-1}{\boldsymbol {r}}\right\|_{p}\leq \|V\|_{p}\left\|\left(D-\lambda ^{a}I\right)^{-1}\right\|_{p}\left\|V^{-1}\right\|_{p}\|{\boldsymbol {r}}\|_{p}=\kappa _{p}(V)\left\|\left(D-\lambda ^{a}I\right)^{-1}\right\|_{p}\|{\boldsymbol {r}}\|_{p}.}$ 

However

${\displaystyle \left(D-\lambda ^{a}I\right)^{-1}}$ 

is a diagonal matrix and its p-norm is easily computed:

${\displaystyle \left\|\left(D-\lambda ^{a}I\right)^{-1}\right\|_{p}=\max _{\|{\boldsymbol {x}}\|_{p}\neq 0}{\frac {\left\|\left(D-\lambda ^{a}I\right)^{-1}{\boldsymbol {x}}\right\|_{p}}{\|{\boldsymbol {x}}\|_{p}}}=\max _{\lambda \in \sigma (A)}{\frac {1}{\left|\lambda -\lambda ^{a}\right|}}={\frac {1}{\min _{\lambda \in \sigma (A)}\left|\lambda -\lambda ^{a}\right|}}}$ 

whence:

${\displaystyle \min _{\lambda \in \lambda (A)}\left|\lambda -\lambda ^{a}\right|\leq \kappa _{p}(V){\frac {\|{\boldsymbol {r}}\|_{p}}{\left\|{\boldsymbol {v}}^{a}\right\|_{p}}}.}$ 

Both formulations of Bauer–Fike theorem yield an absolute bound. The following corollary is useful whenever a relative bound is needed:

Corollary. Suppose A is invertible and that μ is an eigenvalue of A + δA. Then there exists λ ∈ Λ(A) such that:

${\displaystyle {\frac {|\lambda -\mu |}{|\lambda |}}\leq \kappa _{p}(V)\left\|A^{-1}\delta A\right\|_{p}}$ 

Note. ||A⁻¹δA|| can be formally viewed as the relative variation of A, just as ⁠|λ − μ|/|λ|⁠ is the relative variation of λ.

Proof. Since μ is an eigenvalue of A + δA and det(A) ≠ 0, by multiplying by −A⁻¹ from left we have:

${\displaystyle -A^{-1}(A+\delta A){\boldsymbol {v}}=-\mu A^{-1}{\boldsymbol {v}}.}$ 

If we set:

${\displaystyle A^{a}=\mu A^{-1},\qquad (\delta A)^{a}=-A^{-1}\delta A}$ 

then we have:

${\displaystyle \left(A^{a}+(\delta A)^{a}-I\right){\boldsymbol {v}}={\boldsymbol {0}}}$ 

which means that 1 is an eigenvalue of A^a + (δA)^a, with v as an eigenvector. Now, the eigenvalues of A^a are ⁠μ/λ_i⁠, while it has the same eigenvector matrix as A. Applying the Bauer–Fike theorem to A^a + (δA)^a with eigenvalue 1, gives us:

${\displaystyle \min _{\lambda \in \Lambda (A)}\left|{\frac {\mu }{\lambda }}-1\right|=\min _{\lambda \in \Lambda (A)}{\frac {|\lambda -\mu |}{|\lambda |}}\leq \kappa _{p}(V)\left\|A^{-1}\delta A\right\|_{p}}$ 

If A is normal, V is a unitary matrix, therefore:

${\displaystyle \|V\|_{2}=\left\|V^{-1}\right\|_{2}=1,}$ 

so that κ₂(V) = 1. The Bauer–Fike theorem then becomes:

${\displaystyle \exists \lambda \in \Lambda (A):\quad |\lambda -\mu |\leq \|\delta A\|_{2}}$ 

Or in alternate formulation:

${\displaystyle \exists \lambda \in \Lambda (A):\quad \left|\lambda -\lambda ^{a}\right|\leq {\frac {\|{\boldsymbol {r}}\|_{2}}{\left\|{\boldsymbol {v}}^{a}\right\|_{2}}}}$ 

which obviously remains true if A is a Hermitian matrix. In this case, however, a much stronger result holds, known as the Weyl's theorem on eigenvalues. In the hermitian case one can also restate the Bauer–Fike theorem in the form that the map A ↦ Λ(A) that maps a matrix to its spectrum is a non-expansive function with respect to the Hausdorff distance on the set of compact subsets of C.

• Bauer, F. L.; Fike, C. T. (1960). "Norms and Exclusion Theorems". Numer. Math. 2 (1): 137–141. doi:10.1007/BF01386217. S2CID 121278235.
• Eisenstat, S. C.; Ipsen, I. C. F. (1998). "Three absolute perturbation bounds for matrix eigenvalues imply relative bounds". SIAM Journal on Matrix Analysis and Applications. 20 (1): 149–158. CiteSeerX 10.1.1.45.3999. doi:10.1137/S0895479897323282.